14311244141 has 2 divisors, whose sum is σ = 14311244142. Its totient is φ = 14311244140.

The previous prime is 14311244137. The next prime is 14311244173. The reversal of 14311244141 is 14144211341.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13408482025 + 902762116 = 115795^2 + 30046^2 .

It is a cyclic number.

It is not a de Polignac number, because 14311244141 - 2² = 14311244137 is a prime.

It is a super-3 number, since 3×14311244141³ (a number of 31 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 14311244141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14311244111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155622070 + 7155622071.

It is an arithmetic number, because the mean of its divisors is an integer number (7155622071).

Almost surely, 2^14311244141 is an apocalyptic number.

It is an amenable number.

14311244141 is a deficient number, since it is larger than the sum of its proper divisors (1).

14311244141 is an equidigital number, since it uses as much as digits as its factorization.

14311244141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1536, while the sum is 26.

Adding to 14311244141 its reverse (14144211341), we get a palindrome (28455455482).

The spelling of 14311244141 in words is "fourteen billion, three hundred eleven million, two hundred forty-four thousand, one hundred forty-one".