14311311242 has 4 divisors (see below), whose sum is σ = 21466966866. Its totient is φ = 7155655620.

The previous prime is 14311311193. The next prime is 14311311247. The reversal of 14311311242 is 24211311341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24211311341 = 7 ⋅3458758763.

It can be written as a sum of positive squares in only one way, i.e., 14256121201 + 55190041 = 119399^2 + 7429^2 .

It is not an unprimeable number, because it can be changed into a prime (14311311247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3577827809 + ... + 3577827812.

Almost surely, 2^14311311242 is an apocalyptic number.

14311311242 is a deficient number, since it is larger than the sum of its proper divisors (7155655624).

14311311242 is an equidigital number, since it uses as much as digits as its factorization.

14311311242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7155655623.

The product of its digits is 576, while the sum is 23.

Adding to 14311311242 its reverse (24211311341), we get a palindrome (38522622583).

Subtracting 14311311242 from its reverse (24211311341), we obtain a palindrome (9900000099).

The spelling of 14311311242 in words is "fourteen billion, three hundred eleven million, three hundred eleven thousand, two hundred forty-two".