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14311311247 is a prime number
BaseRepresentation
bin11010101010000010…
…10100011110001111
31100221101020221022201
431111001110132033
5213302143424442
610324033022331
71014435065332
oct152501243617
940841227281
1014311311247
1160843a8a62
1229349b49a7
131470c6a30c
1499a992619
1558b6287b7
hex35505478f

14311311247 has 2 divisors, whose sum is σ = 14311311248. Its totient is φ = 14311311246.

The previous prime is 14311311193. The next prime is 14311311253. The reversal of 14311311247 is 74211311341.

14311311247 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14311311247 - 227 = 14177093519 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14311311277) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155655623 + 7155655624.

It is an arithmetic number, because the mean of its divisors is an integer number (7155655624).

Almost surely, 214311311247 is an apocalyptic number.

14311311247 is a deficient number, since it is larger than the sum of its proper divisors (1).

14311311247 is an equidigital number, since it uses as much as digits as its factorization.

14311311247 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2016, while the sum is 28.

Adding to 14311311247 its reverse (74211311341), we get a palindrome (88522622588).

The spelling of 14311311247 in words is "fourteen billion, three hundred eleven million, three hundred eleven thousand, two hundred forty-seven".