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1431132011 is a prime number
BaseRepresentation
bin101010101001101…
…0101011101101011
310200201221001001022
41111103111131223
510412332211021
6354002043055
750315264351
oct12523253553
93621831038
101431132011
11674922731
1233b34948b
1319a65ba9a
14d80d77d1
15859941ab
hex554d576b

1431132011 has 2 divisors, whose sum is σ = 1431132012. Its totient is φ = 1431132010.

The previous prime is 1431131953. The next prime is 1431132061. The reversal of 1431132011 is 1102311341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1431132011 - 214 = 1431115627 is a prime.

It is not a weakly prime, because it can be changed into another prime (1431132061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715566005 + 715566006.

It is an arithmetic number, because the mean of its divisors is an integer number (715566006).

Almost surely, 21431132011 is an apocalyptic number.

1431132011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431132011 is an equidigital number, since it uses as much as digits as its factorization.

1431132011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1431132011 is about 37830.3054573975. The cubic root of 1431132011 is about 1126.9203772650.

Adding to 1431132011 its reverse (1102311341), we get a palindrome (2533443352).

The spelling of 1431132011 in words is "one billion, four hundred thirty-one million, one hundred thirty-two thousand, eleven".