1431142021 has 4 divisors (see below), whose sum is σ = 1431253152. Its totient is φ = 1431030892.

The previous prime is 1431141979. The next prime is 1431142033. The reversal of 1431142021 is 1202411341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1202411341 = 71 ⋅16935371.

It is a cyclic number.

It is not a de Polignac number, because 1431142021 - 2¹⁷ = 1431010949 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1431142021.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431142091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33265 + ... + 62998.

It is an arithmetic number, because the mean of its divisors is an integer number (357813288).

Almost surely, 2^1431142021 is an apocalyptic number.

It is an amenable number.

1431142021 is a deficient number, since it is larger than the sum of its proper divisors (111131).

1431142021 is an equidigital number, since it uses as much as digits as its factorization.

1431142021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111130.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 1431142021 is about 37830.4377585034. The cubic root of 1431142021 is about 1126.9230046599.

Adding to 1431142021 its reverse (1202411341), we get a palindrome (2633553362).

The spelling of 1431142021 in words is "one billion, four hundred thirty-one million, one hundred forty-two thousand, twenty-one".