1431204041222 has 4 divisors (see below), whose sum is σ = 2146806061836. Its totient is φ = 715602020610.

The previous prime is 1431204041161. The next prime is 1431204041251. The reversal of 1431204041222 is 2221404021341.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1431204041222² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1431204041191 and 1431204041200.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 357801010304 + ... + 357801010307.

It is an arithmetic number, because the mean of its divisors is an integer number (536701515459).

Almost surely, 2^{1431204041222} is an apocalyptic number.

1431204041222 is a deficient number, since it is larger than the sum of its proper divisors (715602020614).

1431204041222 is an equidigital number, since it uses as much as digits as its factorization.

1431204041222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 715602020613.

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 1431204041222 its reverse (2221404021341), we get a palindrome (3652608062563).

The spelling of 1431204041222 in words is "one trillion, four hundred thirty-one billion, two hundred four million, forty-one thousand, two hundred twenty-two".