Base | Representation |
---|---|
bin | 10100110100111010111… |
… | …001000000101010011111 |
3 | 12001211012122010102202122 |
4 | 110310322321000222133 |
5 | 141422110301224043 |
6 | 3013253443013155 |
7 | 205254525256301 |
oct | 24647271005237 |
9 | 5054178112678 |
10 | 1431212133023 |
11 | 501a78a34852 |
12 | 1b146606a1bb |
13 | a4c69150b3a |
14 | 4d3b1a21971 |
15 | 273683be368 |
hex | 14d3ae40a9f |
1431212133023 has 2 divisors, whose sum is σ = 1431212133024. Its totient is φ = 1431212133022.
The previous prime is 1431212133007. The next prime is 1431212133047. The reversal of 1431212133023 is 3203312121341.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1431212133023 - 24 = 1431212133007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1431212132983 and 1431212133001.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1431212133073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715606066511 + 715606066512.
It is an arithmetic number, because the mean of its divisors is an integer number (715606066512).
Almost surely, 21431212133023 is an apocalyptic number.
1431212133023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1431212133023 is an equidigital number, since it uses as much as digits as its factorization.
1431212133023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 1431212133023 its reverse (3203312121341), we get a palindrome (4634524254364).
The spelling of 1431212133023 in words is "one trillion, four hundred thirty-one billion, two hundred twelve million, one hundred thirty-three thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •