Base | Representation |
---|---|
bin | 10100110100111011000… |
… | …001110100101001101001 |
3 | 12001211012210110210121112 |
4 | 110310323001310221221 |
5 | 141422111344134423 |
6 | 3013254004320105 |
7 | 205254554020250 |
oct | 24647301645151 |
9 | 5054183423545 |
10 | 1431214443113 |
11 | 501a7a272414 |
12 | 1b14669a3035 |
13 | a4c6977c460 |
14 | 4d3b2063797 |
15 | 273686c8a78 |
hex | 14d3b074a69 |
1431214443113 has 32 divisors (see below), whose sum is σ = 1891381363200. Its totient is φ = 1050767262720.
The previous prime is 1431214443053. The next prime is 1431214443149. The reversal of 1431214443113 is 3113444121341.
It is a happy number.
It is not a de Polignac number, because 1431214443113 - 220 = 1431213394537 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1431214443113.
It is not an unprimeable number, because it can be changed into a prime (1431214443163) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6405338 + ... + 6625011.
It is an arithmetic number, because the mean of its divisors is an integer number (59105667600).
Almost surely, 21431214443113 is an apocalyptic number.
1431214443113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1431214443113 is a deficient number, since it is larger than the sum of its proper divisors (460166920087).
1431214443113 is a wasteful number, since it uses less digits than its factorization.
1431214443113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13030457.
The product of its digits is 13824, while the sum is 32.
Adding to 1431214443113 its reverse (3113444121341), we get a palindrome (4544658564454).
The spelling of 1431214443113 in words is "one trillion, four hundred thirty-one billion, two hundred fourteen million, four hundred forty-three thousand, one hundred thirteen".
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