1431225442541 has 4 divisors (see below), whose sum is σ = 1431227988192. Its totient is φ = 1431222896892.

The previous prime is 1431225442501. The next prime is 1431225442597. The reversal of 1431225442541 is 1452445221341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1431225442541 - 2¹⁴ = 1431225426157 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1431225442495 and 1431225442504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431225442501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15455 + ... + 1691948.

It is an arithmetic number, because the mean of its divisors is an integer number (357806997048).

Almost surely, 2^{1431225442541} is an apocalyptic number.

It is an amenable number.

1431225442541 is a deficient number, since it is larger than the sum of its proper divisors (2545651).

1431225442541 is an equidigital number, since it uses as much as digits as its factorization.

1431225442541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2545650.

The product of its digits is 153600, while the sum is 38.

The spelling of 1431225442541 in words is "one trillion, four hundred thirty-one billion, two hundred twenty-five million, four hundred forty-two thousand, five hundred forty-one".