Base | Representation |
---|---|
bin | 100000100010101110101001… |
… | …101000011011111110001101 |
3 | 200202202112011111211100021121 |
4 | 200202232221220123332031 |
5 | 122224421014013420240 |
6 | 1224222135443000541 |
7 | 42101241106666021 |
oct | 4042565150337615 |
9 | 622675144740247 |
10 | 143124041154445 |
11 | 41670623aa51aa |
12 | 14076493969151 |
13 | 61b27017284c0 |
14 | 274b352114381 |
15 | 1182eb888a04a |
hex | 822ba9a1bf8d |
143124041154445 has 16 divisors (see below), whose sum is σ = 184966028553600. Its totient is φ = 105688325784384.
The previous prime is 143124041154427. The next prime is 143124041154503. The reversal of 143124041154445 is 544451140421341.
143124041154445 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 143124041154445 - 213 = 143124041146253 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31986889 + ... + 36185758.
It is an arithmetic number, because the mean of its divisors is an integer number (11560376784600).
Almost surely, 2143124041154445 is an apocalyptic number.
It is an amenable number.
143124041154445 is a deficient number, since it is larger than the sum of its proper divisors (41841987399155).
143124041154445 is a wasteful number, since it uses less digits than its factorization.
143124041154445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68204964.
The product of its (nonzero) digits is 614400, while the sum is 43.
Adding to 143124041154445 its reverse (544451140421341), we get a palindrome (687575181575786).
The spelling of 143124041154445 in words is "one hundred forty-three trillion, one hundred twenty-four billion, forty-one million, one hundred fifty-four thousand, four hundred forty-five".
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