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14312427013 = 76031882471
BaseRepresentation
bin11010101010001011…
…00100111000000101
31100221110100121212101
431111011210320011
5213302440131023
610324112552101
71014450423313
oct152505447005
940843317771
1014312427013
116084aa0285
122935252631
13147126b131
1499aba30b3
1558b7991ad
hex355164e05

14312427013 has 4 divisors (see below), whose sum is σ = 14314317088. Its totient is φ = 14310536940.

The previous prime is 14312426969. The next prime is 14312427023. The reversal of 14312427013 is 31072421341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31072421341 = 132390186257.

It is a cyclic number.

It is not a de Polignac number, because 14312427013 - 213 = 14312418821 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14312427023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 933633 + ... + 948838.

It is an arithmetic number, because the mean of its divisors is an integer number (3578579272).

Almost surely, 214312427013 is an apocalyptic number.

It is an amenable number.

14312427013 is a deficient number, since it is larger than the sum of its proper divisors (1890075).

14312427013 is an equidigital number, since it uses as much as digits as its factorization.

14312427013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1890074.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 14312427013 its reverse (31072421341), we get a palindrome (45384848354).

The spelling of 14312427013 in words is "fourteen billion, three hundred twelve million, four hundred twenty-seven thousand, thirteen".

Divisors: 1 7603 1882471 14312427013