Base | Representation |
---|---|
bin | 100000100010110000101100… |
… | …011010000111010011111111 |
3 | 200202202201211102100011200110 |
4 | 200202300230122013103333 |
5 | 122224440012203340403 |
6 | 1224223141301201103 |
7 | 42101346351130230 |
oct | 4042605432072377 |
9 | 622681742304613 |
10 | 143126235215103 |
11 | 4167154a538478 |
12 | 140769a6700193 |
13 | 61b299115a64a |
14 | 274b4bd687087 |
15 | 11830962d2103 |
hex | 822c2c6874ff |
143126235215103 has 64 divisors (see below), whose sum is σ = 231904981942272. Its totient is φ = 76754861694720.
The previous prime is 143126235215023. The next prime is 143126235215123. The reversal of 143126235215103 is 301512532621341.
It is not a de Polignac number, because 143126235215103 - 29 = 143126235214591 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143126235215123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3891925 + ... + 17360862.
It is an arithmetic number, because the mean of its divisors is an integer number (3623515342848).
Almost surely, 2143126235215103 is an apocalyptic number.
143126235215103 is a deficient number, since it is larger than the sum of its proper divisors (88778746727169).
143126235215103 is a wasteful number, since it uses less digits than its factorization.
143126235215103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21253084.
The product of its (nonzero) digits is 129600, while the sum is 39.
Adding to 143126235215103 its reverse (301512532621341), we get a palindrome (444638767836444).
The spelling of 143126235215103 in words is "one hundred forty-three trillion, one hundred twenty-six billion, two hundred thirty-five million, two hundred fifteen thousand, one hundred three".
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