143130052146343 has 8 divisors (see below), whose sum is σ = 146999181989520. Its totient is φ = 139260961779840.

The previous prime is 143130052146317. The next prime is 143130052146469. The reversal of 143130052146343 is 343641250031341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 143130052146343 - 2²¹ = 143130050049191 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143130052146296 and 143130052146305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143130052146313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2445313 + ... + 17095018.

It is an arithmetic number, because the mean of its divisors is an integer number (18374897748690).

Almost surely, 2^{143130052146343} is an apocalyptic number.

143130052146343 is a deficient number, since it is larger than the sum of its proper divisors (3869129843177).

143130052146343 is a wasteful number, since it uses less digits than its factorization.

143130052146343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19738337.

The product of its (nonzero) digits is 311040, while the sum is 40.

The spelling of 143130052146343 in words is "one hundred forty-three trillion, one hundred thirty billion, fifty-two million, one hundred forty-six thousand, three hundred forty-three".