143130255407 has 4 divisors (see below), whose sum is σ = 143131524480. Its totient is φ = 143128986336.

The previous prime is 143130255391. The next prime is 143130255427. The reversal of 143130255407 is 704552031341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 143130255407 - 2⁴ = 143130255391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143130255427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 446858 + ... + 697095.

It is an arithmetic number, because the mean of its divisors is an integer number (35782881120).

Almost surely, 2^143130255407 is an apocalyptic number.

143130255407 is a deficient number, since it is larger than the sum of its proper divisors (1269073).

143130255407 is a wasteful number, since it uses less digits than its factorization.

143130255407 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1269072.

The product of its (nonzero) digits is 50400, while the sum is 35.

Adding to 143130255407 its reverse (704552031341), we get a palindrome (847682286748).

The spelling of 143130255407 in words is "one hundred forty-three billion, one hundred thirty million, two hundred fifty-five thousand, four hundred seven".