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1431304021121 = 131056491042133
BaseRepresentation
bin10100110101000000010…
…111100010010010000001
312001211110001000211112112
4110311000113202102001
5141422302312133441
63013310524305105
7205260022304522
oct24650027422201
95054401024475
101431304021121
11502015895727
121b14909a2195
13a4c821b42b0
144d3bdd00849
15273714c04eb
hex14d405e2481

1431304021121 has 8 divisors (see below), whose sum is σ = 1541420399400. Its totient is φ = 1321189938432.

The previous prime is 1431304021067. The next prime is 1431304021139. The reversal of 1431304021121 is 1211204031341.

It can be written as a sum of positive squares in 4 ways, for example, as 55759738225 + 1375544282896 = 236135^2 + 1172836^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-1431304021121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1431304021141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 852371 + ... + 1894503.

It is an arithmetic number, because the mean of its divisors is an integer number (192677549925).

Almost surely, 21431304021121 is an apocalyptic number.

It is an amenable number.

1431304021121 is a deficient number, since it is larger than the sum of its proper divisors (110116378279).

1431304021121 is a wasteful number, since it uses less digits than its factorization.

1431304021121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1147795.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1431304021121 its reverse (1211204031341), we get a palindrome (2642508052462).

The spelling of 1431304021121 in words is "one trillion, four hundred thirty-one billion, three hundred four million, twenty-one thousand, one hundred twenty-one".

Divisors: 1 13 105649 1042133 1373437 13547729 110100309317 1431304021121