Base | Representation |
---|---|
bin | 100000100010110101011011… |
… | …001000111100110100100010 |
3 | 200202210012221101100221210110 |
4 | 200202311123020330310202 |
5 | 122230030412414242010 |
6 | 1224225341253512150 |
7 | 42101616252652566 |
oct | 4042653310746442 |
9 | 622705841327713 |
10 | 143131314212130 |
11 | 416737164a1082 |
12 | 14077983642656 |
13 | 61b32c0487c2a |
14 | 274b84202d6a6 |
15 | 1183292140120 |
hex | 822d5b23cd22 |
143131314212130 has 16 divisors (see below), whose sum is σ = 343515154109184. Its totient is φ = 38168350456560.
The previous prime is 143131314212119. The next prime is 143131314212197. The reversal of 143131314212130 is 31212413131341.
It is a happy number.
143131314212130 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (30), and also a Moran number because the ratio is a prime number: 4771043807071 = 143131314212130 / (1 + 4 + 3 + 1 + 3 + 1 + 3 + 1 + 4 + 2 + 1 + 2 + 1 + 3 + 0).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2385521903506 + ... + 2385521903565.
It is an arithmetic number, because the mean of its divisors is an integer number (21469697131824).
Almost surely, 2143131314212130 is an apocalyptic number.
143131314212130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
143131314212130 is an abundant number, since it is smaller than the sum of its proper divisors (200383839897054).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143131314212130 is a wasteful number, since it uses less digits than its factorization.
143131314212130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4771043807081.
The product of its (nonzero) digits is 5184, while the sum is 30.
Adding to 143131314212130 its reverse (31212413131341), we get a palindrome (174343727343471).
The spelling of 143131314212130 in words is "one hundred forty-three trillion, one hundred thirty-one billion, three hundred fourteen million, two hundred twelve thousand, one hundred thirty".
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