Base | Representation |
---|---|
bin | 1000010101001101010… |
… | …0010001001111110110 |
3 | 111200110002121220210220 |
4 | 2011103110101033312 |
5 | 4321113211240342 |
6 | 145430453555210 |
7 | 13224636513006 |
oct | 2052324211766 |
9 | 450402556726 |
10 | 143131743222 |
11 | 5577a157186 |
12 | 238a6645b06 |
13 | 106606525b0 |
14 | 6cdb52a006 |
15 | 3acab3a5ec |
hex | 21535113f6 |
143131743222 has 64 divisors (see below), whose sum is σ = 315948487680. Its totient is φ = 42959015424.
The previous prime is 143131743211. The next prime is 143131743247. The reversal of 143131743222 is 222347131341.
143131743222 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 371518 + ... + 651374.
It is an arithmetic number, because the mean of its divisors is an integer number (4936695120).
Almost surely, 2143131743222 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 143131743222, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (157974243840).
143131743222 is an abundant number, since it is smaller than the sum of its proper divisors (172816744458).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143131743222 is a wasteful number, since it uses less digits than its factorization.
143131743222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 280037.
The product of its digits is 24192, while the sum is 33.
Adding to 143131743222 its reverse (222347131341), we get a palindrome (365478874563).
The spelling of 143131743222 in words is "one hundred forty-three billion, one hundred thirty-one million, seven hundred forty-three thousand, two hundred twenty-two".
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