143132212505453 has 8 divisors (see below), whose sum is σ = 143758375169400. Its totient is φ = 142506059678208.

The previous prime is 143132212505449. The next prime is 143132212505561. The reversal of 143132212505453 is 354505212231341.

It can be written as a sum of positive squares in 4 ways, for example, as 64246605098404 + 78885607407049 = 8015398^2 + 8881757^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 143132212505453 - 2² = 143132212505449 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 143132212505453.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143132212405453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27502853 + ... + 32290421.

It is an arithmetic number, because the mean of its divisors is an integer number (17969796896175).

Almost surely, 2^{143132212505453} is an apocalyptic number.

It is an amenable number.

143132212505453 is a deficient number, since it is larger than the sum of its proper divisors (626162663947).

143132212505453 is a wasteful number, since it uses less digits than its factorization.

143132212505453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4918351.

The product of its (nonzero) digits is 432000, while the sum is 41.

Adding to 143132212505453 its reverse (354505212231341), we get a palindrome (497637424736794).

The spelling of 143132212505453 in words is "one hundred forty-three trillion, one hundred thirty-two billion, two hundred twelve million, five hundred five thousand, four hundred fifty-three".