1431335503453 has 4 divisors (see below), whose sum is σ = 1493567481888. Its totient is φ = 1369103525020.

The previous prime is 1431335503417. The next prime is 1431335503457. The reversal of 1431335503453 is 3543055331341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1431335503453 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431335503457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31115989183 + ... + 31115989228.

It is an arithmetic number, because the mean of its divisors is an integer number (373391870472).

Almost surely, 2^{1431335503453} is an apocalyptic number.

It is an amenable number.

1431335503453 is a deficient number, since it is larger than the sum of its proper divisors (62231978435).

1431335503453 is an equidigital number, since it uses as much as digits as its factorization.

1431335503453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62231978434.

The product of its (nonzero) digits is 486000, while the sum is 40.

The spelling of 1431335503453 in words is "one trillion, four hundred thirty-one billion, three hundred thirty-five million, five hundred three thousand, four hundred fifty-three".