143134402025543 has 2 divisors, whose sum is σ = 143134402025544. Its totient is φ = 143134402025542.

The previous prime is 143134402025519. The next prime is 143134402025557. The reversal of 143134402025543 is 345520204431341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 143134402025543 - 2¹⁰ = 143134402024519 is a prime.

It is a super-2 number, since 2×143134402025543² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 143134402025543.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143134402025743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71567201012771 + 71567201012772.

It is an arithmetic number, because the mean of its divisors is an integer number (71567201012772).

Almost surely, 2^{143134402025543} is an apocalyptic number.

143134402025543 is a deficient number, since it is larger than the sum of its proper divisors (1).

143134402025543 is an equidigital number, since it uses as much as digits as its factorization.

143134402025543 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 41.

Adding to 143134402025543 its reverse (345520204431341), we get a palindrome (488654606456884).

The spelling of 143134402025543 in words is "one hundred forty-three trillion, one hundred thirty-four billion, four hundred two million, twenty-five thousand, five hundred forty-three".