14314041341 has 4 divisors (see below), whose sum is σ = 14314328832. Its totient is φ = 14313753852.

The previous prime is 14314041331. The next prime is 14314041367.

It is a happy number.

14314041341 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14314041341 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14314041341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14314041311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47645 + ... + 175778.

It is an arithmetic number, because the mean of its divisors is an integer number (3578582208).

Almost surely, 2^14314041341 is an apocalyptic number.

It is an amenable number.

14314041341 is a deficient number, since it is larger than the sum of its proper divisors (287491).

14314041341 is an equidigital number, since it uses as much as digits as its factorization.

14314041341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 287490.

The product of its (nonzero) digits is 2304, while the sum is 26.

It can be divided in two parts, 143140 and 41341, that added together give a palindrome (184481).

The spelling of 14314041341 in words is "fourteen billion, three hundred fourteen million, forty-one thousand, three hundred forty-one".