14314120397 has 2 divisors, whose sum is σ = 14314120398. Its totient is φ = 14314120396.

The previous prime is 14314120333. The next prime is 14314120399. The reversal of 14314120397 is 79302141341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7253247556 + 7060872841 = 85166^2 + 84029^2 .

It is a cyclic number.

It is not a de Polignac number, because 14314120397 - 2⁶ = 14314120333 is a prime.

It is a super-2 number, since 2×14314120397² (a number of 21 digits) contains 22 as substring.

Together with 14314120399, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14314120399) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157060198 + 7157060199.

It is an arithmetic number, because the mean of its divisors is an integer number (7157060199).

Almost surely, 2^14314120397 is an apocalyptic number.

It is an amenable number.

14314120397 is a deficient number, since it is larger than the sum of its proper divisors (1).

14314120397 is an equidigital number, since it uses as much as digits as its factorization.

14314120397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 35.

The spelling of 14314120397 in words is "fourteen billion, three hundred fourteen million, one hundred twenty thousand, three hundred ninety-seven".