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143141344103 = 319674775039
BaseRepresentation
bin1000010101001111100…
…0111001001101100111
3111200110202200200202002
42011103320321031213
54321123141002403
6145431435435515
713225114230632
oct2052370711547
9450422620662
10143141344103
115578461449a
12238a98b5b9b
13106626345a4
146cdc908c19
153acb8d5188
hex2153e39367

143141344103 has 8 divisors (see below), whose sum is σ = 147911639040. Its totient is φ = 138380601240.

The previous prime is 143141344063. The next prime is 143141344109. The reversal of 143141344103 is 301443141341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143141344103 is a prime.

It is a super-2 number, since 2×1431413441032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143141344109) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2357543 + ... + 2417496.

It is an arithmetic number, because the mean of its divisors is an integer number (18488954880).

Almost surely, 2143141344103 is an apocalyptic number.

143141344103 is a deficient number, since it is larger than the sum of its proper divisors (4770294937).

143141344103 is an equidigital number, since it uses as much as digits as its factorization.

143141344103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4776037.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 143141344103 its reverse (301443141341), we get a palindrome (444584485444).

The spelling of 143141344103 in words is "one hundred forty-three billion, one hundred forty-one million, three hundred forty-four thousand, one hundred three".

Divisors: 1 31 967 29977 4775039 148026209 4617462713 143141344103