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143144113001 = 239836331289
BaseRepresentation
bin1000010101010000001…
…1011101001101101001
3111200110221220100221212
42011110003131031221
54321124343104001
6145432015042505
713225146612341
oct2052403351551
9450427810855
10143144113001
115578613583a
12238aa810435
13106630939a6
146cdd029d21
153acbc807bb
hex21540dd369

143144113001 has 8 divisors (see below), whose sum is σ = 149519744640. Its totient is φ = 136781145952.

The previous prime is 143144112973. The next prime is 143144113009. The reversal of 143144113001 is 100311441341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 143144113001 - 222 = 143139918697 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (23).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143144113009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3143036 + ... + 3188253.

It is an arithmetic number, because the mean of its divisors is an integer number (18689968080).

Almost surely, 2143144113001 is an apocalyptic number.

It is an amenable number.

143144113001 is a deficient number, since it is larger than the sum of its proper divisors (6375631639).

143144113001 is an equidigital number, since it uses as much as digits as its factorization.

143144113001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6332295.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 143144113001 its reverse (100311441341), we get a palindrome (243455554342).

The spelling of 143144113001 in words is "one hundred forty-three billion, one hundred forty-four million, one hundred thirteen thousand, one".

Divisors: 1 23 983 22609 6331289 145619647 6223657087 143144113001