14314543010500 has 48 divisors (see below), whose sum is σ = 31263332091264. Its totient is φ = 5725749410400.

The previous prime is 14314543010461. The next prime is 14314543010501. The reversal of 14314543010500 is 501034541341.

It is a super-3 number, since 3×14314543010500³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (14314543010501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 79751857 + ... + 79931143.

It is an arithmetic number, because the mean of its divisors is an integer number (651319418568).

Almost surely, 2^{14314543010500} is an apocalyptic number.

14314543010500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14314543010500 is an abundant number, since it is smaller than the sum of its proper divisors (16948789080764).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14314543010500 is a wasteful number, since it uses less digits than its factorization.

14314543010500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 338989 (or 338977 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 14314543010500 its reverse (501034541341), we get a palindrome (14815577551841).

The spelling of 14314543010500 in words is "fourteen trillion, three hundred fourteen billion, five hundred forty-three million, ten thousand, five hundred".