143187587441 has 2 divisors, whose sum is σ = 143187587442. Its totient is φ = 143187587440.

The previous prime is 143187587381. The next prime is 143187587443. The reversal of 143187587441 is 144785781341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 140116211041 + 3071376400 = 374321^2 + 55420^2 .

It is an emirp because it is prime and its reverse (144785781341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-143187587441 is a prime.

Together with 143187587443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (143187587443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71593793720 + 71593793721.

It is an arithmetic number, because the mean of its divisors is an integer number (71593793721).

Almost surely, 2^143187587441 is an apocalyptic number.

It is an amenable number.

143187587441 is a deficient number, since it is larger than the sum of its proper divisors (1).

143187587441 is an equidigital number, since it uses as much as digits as its factorization.

143187587441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3010560, while the sum is 53.

The spelling of 143187587441 in words is "one hundred forty-three billion, one hundred eighty-seven million, five hundred eighty-seven thousand, four hundred forty-one".