143201401311031 has 4 divisors (see below), whose sum is σ = 163658744355472. Its totient is φ = 122744058266592.

The previous prime is 143201401311011. The next prime is 143201401311097. The reversal of 143201401311031 is 130113104102341.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 143201401311031 - 2²⁹ = 143200864440119 is a prime.

It is a super-2 number, since 2×143201401311031² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143201401310987 and 143201401311005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143201401311011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10228671522210 + ... + 10228671522223.

It is an arithmetic number, because the mean of its divisors is an integer number (40914686088868).

Almost surely, 2^{143201401311031} is an apocalyptic number.

143201401311031 is a deficient number, since it is larger than the sum of its proper divisors (20457343044441).

143201401311031 is an equidigital number, since it uses as much as digits as its factorization.

143201401311031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20457343044440.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 143201401311031 its reverse (130113104102341), we get a palindrome (273314505413372).

The spelling of 143201401311031 in words is "one hundred forty-three trillion, two hundred one billion, four hundred one million, three hundred eleven thousand, thirty-one".