Base | Representation |
---|---|
bin | 1101000001101001101001… |
… | …1001000000110111110101 |
3 | 1212201011121120211110201220 |
4 | 3100122122121000313311 |
5 | 3334122434332311201 |
6 | 50243235140540553 |
7 | 3005505534453441 |
oct | 320323231006765 |
9 | 55634546743656 |
10 | 14322011213301 |
11 | 4621a26a57260 |
12 | 17338506b1759 |
13 | 7cb73802c70c |
14 | 377290a2d821 |
15 | 19c835ba3036 |
hex | d069a640df5 |
14322011213301 has 32 divisors (see below), whose sum is σ = 20848560585216. Its totient is φ = 8673115608000.
The previous prime is 14322011213249. The next prime is 14322011213327. The reversal of 14322011213301 is 10331211022341.
It is not a de Polignac number, because 14322011213301 - 27 = 14322011213173 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14322011213201) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 287872110 + ... + 287921856.
It is an arithmetic number, because the mean of its divisors is an integer number (651517518288).
Almost surely, 214322011213301 is an apocalyptic number.
14322011213301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
14322011213301 is a deficient number, since it is larger than the sum of its proper divisors (6526549371915).
14322011213301 is a wasteful number, since it uses less digits than its factorization.
14322011213301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56513.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 14322011213301 its reverse (10331211022341), we get a palindrome (24653222235642).
The spelling of 14322011213301 in words is "fourteen trillion, three hundred twenty-two billion, eleven million, two hundred thirteen thousand, three hundred one".
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