Base | Representation |
---|---|
bin | 11010101011011100… |
… | …11000011100100101 |
3 | 1100222012111002101021 |
4 | 31111232120130211 |
5 | 213313204432010 |
6 | 10325134131141 |
7 | 1014640355011 |
oct | 152556303445 |
9 | 40865432337 |
10 | 14323124005 |
11 | 6090037073 |
12 | 2938950ab1 |
13 | 1473545008 |
14 | 99c389541 |
15 | 58c6ad8da |
hex | 355b98725 |
14323124005 has 8 divisors (see below), whose sum is σ = 17188952472. Its totient is φ = 11457696768.
The previous prime is 14323124003. The next prime is 14323124047. The reversal of 14323124005 is 50042132341.
It can be written as a sum of positive squares in 4 ways, for example, as 1290390084 + 13032733921 = 35922^2 + 114161^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14323124005 - 21 = 14323124003 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14323124003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15204 + ... + 169933.
It is an arithmetic number, because the mean of its divisors is an integer number (2148619059).
Almost surely, 214323124005 is an apocalyptic number.
It is an amenable number.
14323124005 is a deficient number, since it is larger than the sum of its proper divisors (2865828467).
14323124005 is a wasteful number, since it uses less digits than its factorization.
14323124005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 200615.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 14323124005 its reverse (50042132341), we get a palindrome (64365256346).
The spelling of 14323124005 in words is "fourteen billion, three hundred twenty-three million, one hundred twenty-four thousand, five".
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