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143242111543 is a prime number
BaseRepresentation
bin1000010101100111100…
…1010010101000110111
3111200201210022012200111
42011121321102220313
54321324440032133
6145445435323451
713230446600356
oct2053171225067
9450653265614
10143242111543
115582648a573
12239175b0587
131067a4864ab
146d0c05999d
153ad568c1cd
hex2159e52a37

143242111543 has 2 divisors, whose sum is σ = 143242111544. Its totient is φ = 143242111542.

The previous prime is 143242111499. The next prime is 143242111549. The reversal of 143242111543 is 345111242341.

It is a happy number.

143242111543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (345111242341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143242111543 - 225 = 143208557111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143242111549) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71621055771 + 71621055772.

It is an arithmetic number, because the mean of its divisors is an integer number (71621055772).

Almost surely, 2143242111543 is an apocalyptic number.

143242111543 is a deficient number, since it is larger than the sum of its proper divisors (1).

143242111543 is an equidigital number, since it uses as much as digits as its factorization.

143242111543 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11520, while the sum is 31.

Adding to 143242111543 its reverse (345111242341), we get a palindrome (488353353884).

The spelling of 143242111543 in words is "one hundred forty-three billion, two hundred forty-two million, one hundred eleven thousand, five hundred forty-three".