Base | Representation |
---|---|
bin | 1101000001110010011000… |
… | …0110110100001110010101 |
3 | 1212201101122221120000220021 |
4 | 3100130212012310032111 |
5 | 3334142234421100031 |
6 | 50244303513505141 |
7 | 3005620606460023 |
oct | 320344606641625 |
9 | 55641587500807 |
10 | 14324355253141 |
11 | 4622a1a11806a |
12 | 17341a57121b1 |
13 | 7cba1c85413b |
14 | 377434083713 |
15 | 19c921873511 |
hex | d07261b4395 |
14324355253141 has 2 divisors, whose sum is σ = 14324355253142. Its totient is φ = 14324355253140.
The previous prime is 14324355253123. The next prime is 14324355253151. The reversal of 14324355253141 is 14135255342341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14053096572516 + 271258680625 = 3748746^2 + 520825^2 .
It is a cyclic number.
It is not a de Polignac number, because 14324355253141 - 211 = 14324355251093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14324355253151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162177626570 + 7162177626571.
It is an arithmetic number, because the mean of its divisors is an integer number (7162177626571).
Almost surely, 214324355253141 is an apocalyptic number.
It is an amenable number.
14324355253141 is a deficient number, since it is larger than the sum of its proper divisors (1).
14324355253141 is an equidigital number, since it uses as much as digits as its factorization.
14324355253141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 864000, while the sum is 43.
The spelling of 14324355253141 in words is "fourteen trillion, three hundred twenty-four billion, three hundred fifty-five million, two hundred fifty-three thousand, one hundred forty-one".
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