Base | Representation |
---|---|
bin | 1101000001110010011000… |
… | …0110110100001110011111 |
3 | 1212201101122221120000220122 |
4 | 3100130212012310032133 |
5 | 3334142234421100101 |
6 | 50244303513505155 |
7 | 3005620606460036 |
oct | 320344606641637 |
9 | 55641587500818 |
10 | 14324355253151 |
11 | 4622a1a118079 |
12 | 17341a57121bb |
13 | 7cba1c854148 |
14 | 37743408371d |
15 | 19c92187351b |
hex | d07261b439f |
14324355253151 has 2 divisors, whose sum is σ = 14324355253152. Its totient is φ = 14324355253150.
The previous prime is 14324355253141. The next prime is 14324355253157. The reversal of 14324355253151 is 15135255342341.
14324355253151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14324355253151 - 218 = 14324354991007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14324355253157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162177626575 + 7162177626576.
It is an arithmetic number, because the mean of its divisors is an integer number (7162177626576).
Almost surely, 214324355253151 is an apocalyptic number.
14324355253151 is a deficient number, since it is larger than the sum of its proper divisors (1).
14324355253151 is an equidigital number, since it uses as much as digits as its factorization.
14324355253151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1080000, while the sum is 44.
The spelling of 14324355253151 in words is "fourteen trillion, three hundred twenty-four billion, three hundred fifty-five million, two hundred fifty-three thousand, one hundred fifty-one".
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