Base | Representation |
---|---|
bin | 1101000001110101010001… |
… | …1101111001000001000101 |
3 | 1212201110200011010102010021 |
4 | 3100131110131321001011 |
5 | 3334200333030212041 |
6 | 50244513020455141 |
7 | 3005646102615046 |
oct | 320352435710105 |
9 | 55643604112107 |
10 | 14325133054021 |
11 | 4623289176409 |
12 | 17343820aa4b1 |
13 | 7cbb14a3394a |
14 | 3774a94b08cd |
15 | 19c969cb2cd1 |
hex | d0754779045 |
14325133054021 has 2 divisors, whose sum is σ = 14325133054022. Its totient is φ = 14325133054020.
The previous prime is 14325133053977. The next prime is 14325133054033. The reversal of 14325133054021 is 12045033152341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14321789323396 + 3343730625 = 3784414^2 + 57825^2 .
It is a cyclic number.
It is not a de Polignac number, because 14325133054021 - 213 = 14325133045829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14325133054121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162566527010 + 7162566527011.
It is an arithmetic number, because the mean of its divisors is an integer number (7162566527011).
Almost surely, 214325133054021 is an apocalyptic number.
It is an amenable number.
14325133054021 is a deficient number, since it is larger than the sum of its proper divisors (1).
14325133054021 is an equidigital number, since it uses as much as digits as its factorization.
14325133054021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 34.
The spelling of 14325133054021 in words is "fourteen trillion, three hundred twenty-five billion, one hundred thirty-three million, fifty-four thousand, twenty-one".
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