Search a number
-
+
14325133054033 is a prime number
BaseRepresentation
bin1101000001110101010001…
…1101111001000001010001
31212201110200011010102010201
43100131110131321001101
53334200333030212113
650244513020455201
73005646102615064
oct320352435710121
955643604112121
1014325133054033
11462328917641a
1217343820aa501
137cbb14a33959
143774a94b08db
1519c969cb2cdd
hexd0754779051

14325133054033 has 2 divisors, whose sum is σ = 14325133054034. Its totient is φ = 14325133054032.

The previous prime is 14325133054021. The next prime is 14325133054039. The reversal of 14325133054033 is 33045033152341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7204865219344 + 7120267834689 = 2684188^2 + 2668383^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14325133054033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14325133053983 and 14325133054001.

It is not a weakly prime, because it can be changed into another prime (14325133054039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162566527016 + 7162566527017.

It is an arithmetic number, because the mean of its divisors is an integer number (7162566527017).

Almost surely, 214325133054033 is an apocalyptic number.

It is an amenable number.

14325133054033 is a deficient number, since it is larger than the sum of its proper divisors (1).

14325133054033 is an equidigital number, since it uses as much as digits as its factorization.

14325133054033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 37.

The spelling of 14325133054033 in words is "fourteen trillion, three hundred twenty-five billion, one hundred thirty-three million, fifty-four thousand, thirty-three".