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14325133054039 is a prime number
BaseRepresentation
bin1101000001110101010001…
…1101111001000001010111
31212201110200011010102010221
43100131110131321001113
53334200333030212124
650244513020455211
73005646102615103
oct320352435710127
955643604112127
1014325133054039
114623289176425
1217343820aa507
137cbb14a33962
143774a94b0903
1519c969cb2ce4
hexd0754779057

14325133054039 has 2 divisors, whose sum is σ = 14325133054040. Its totient is φ = 14325133054038.

The previous prime is 14325133054033. The next prime is 14325133054069. The reversal of 14325133054039 is 93045033152341.

14325133054039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14325133054039 - 27 = 14325133053911 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14325133053986 and 14325133054004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14325133054033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162566527019 + 7162566527020.

It is an arithmetic number, because the mean of its divisors is an integer number (7162566527020).

Almost surely, 214325133054039 is an apocalyptic number.

14325133054039 is a deficient number, since it is larger than the sum of its proper divisors (1).

14325133054039 is an equidigital number, since it uses as much as digits as its factorization.

14325133054039 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 583200, while the sum is 43.

The spelling of 14325133054039 in words is "fourteen trillion, three hundred twenty-five billion, one hundred thirty-three million, fifty-four thousand, thirty-nine".