Base | Representation |
---|---|
bin | 1101000001111001000000… |
… | …0110010011110000001011 |
3 | 1212201120020212122120220112 |
4 | 3100132100012103300023 |
5 | 3334204410134130120 |
6 | 50245200155544535 |
7 | 3006012641404622 |
oct | 320362006236013 |
9 | 55646225576815 |
10 | 14326133505035 |
11 | 4623751978030 |
12 | 173460115b14b |
13 | 7cbc4409b1b1 |
14 | 3775622d86b9 |
15 | 19c9c7a32bc5 |
hex | d0790193c0b |
14326133505035 has 32 divisors (see below), whose sum is σ = 18899060958144. Its totient is φ = 10338598144000.
The previous prime is 14326133504987. The next prime is 14326133505041. The reversal of 14326133505035 is 53050533162341.
It is not a de Polignac number, because 14326133505035 - 242 = 9928086993931 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14326133504983 and 14326133505001.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17541575 + ... + 18340095.
It is an arithmetic number, because the mean of its divisors is an integer number (590595654942).
Almost surely, 214326133505035 is an apocalyptic number.
14326133505035 is a deficient number, since it is larger than the sum of its proper divisors (4572927453109).
14326133505035 is a wasteful number, since it uses less digits than its factorization.
14326133505035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 801055.
The product of its (nonzero) digits is 486000, while the sum is 41.
Adding to 14326133505035 its reverse (53050533162341), we get a palindrome (67376666667376).
The spelling of 14326133505035 in words is "fourteen trillion, three hundred twenty-six billion, one hundred thirty-three million, five hundred five thousand, thirty-five".
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