14326133505041 has 2 divisors, whose sum is σ = 14326133505042. Its totient is φ = 14326133505040.

The previous prime is 14326133504987. The next prime is 14326133505043. The reversal of 14326133505041 is 14050533162341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12841500918016 + 1484632587025 = 3583504^2 + 1218455^2 .

It is a cyclic number.

It is not a de Polignac number, because 14326133505041 - 2¹⁰ = 14326133504017 is a prime.

Together with 14326133505043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14326133504986 and 14326133505004.

It is not a weakly prime, because it can be changed into another prime (14326133505043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7163066752520 + 7163066752521.

It is an arithmetic number, because the mean of its divisors is an integer number (7163066752521).

Almost surely, 2^{14326133505041} is an apocalyptic number.

It is an amenable number.

14326133505041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14326133505041 is an equidigital number, since it uses as much as digits as its factorization.

14326133505041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 38.

Adding to 14326133505041 its reverse (14050533162341), we get a palindrome (28376666667382).

The spelling of 14326133505041 in words is "fourteen trillion, three hundred twenty-six billion, one hundred thirty-three million, five hundred five thousand, forty-one".