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14328083390417 is a prime number
BaseRepresentation
bin1101000010000000010001…
…0100100001111111010001
31212201202021202201000210122
43100200010110201333101
53334222403321443132
650250121452440025
73006112156223636
oct320400424417721
955652252630718
1014328083390417
1146245625a5855
121734a66179015
137cc195049c24
143776a926a18d
1519ca8dce6912
hexd0804521fd1

14328083390417 has 2 divisors, whose sum is σ = 14328083390418. Its totient is φ = 14328083390416.

The previous prime is 14328083390347. The next prime is 14328083390419. The reversal of 14328083390417 is 71409338082341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14190168456256 + 137914934161 = 3766984^2 + 371369^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14328083390417 is a prime.

Together with 14328083390419, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14328083390419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7164041695208 + 7164041695209.

It is an arithmetic number, because the mean of its divisors is an integer number (7164041695209).

Almost surely, 214328083390417 is an apocalyptic number.

It is an amenable number.

14328083390417 is a deficient number, since it is larger than the sum of its proper divisors (1).

14328083390417 is an equidigital number, since it uses as much as digits as its factorization.

14328083390417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3483648, while the sum is 53.

The spelling of 14328083390417 in words is "fourteen trillion, three hundred twenty-eight billion, eighty-three million, three hundred ninety thousand, four hundred seventeen".