Base | Representation |
---|---|
bin | 11010101100010010… |
… | …01100101010010111 |
3 | 1100222200201020012111 |
4 | 31112021030222113 |
5 | 213322004403443 |
6 | 10325544531451 |
7 | 1015054203352 |
oct | 152611145227 |
9 | 40880636174 |
10 | 14330153623 |
11 | 6093aa8575 |
12 | 293b180b87 |
13 | 1474b36856 |
14 | 99d299299 |
15 | 58d0eb69d |
hex | 35624ca97 |
14330153623 has 2 divisors, whose sum is σ = 14330153624. Its totient is φ = 14330153622.
The previous prime is 14330153603. The next prime is 14330153627. The reversal of 14330153623 is 32635103341.
14330153623 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14330153623 is a prime.
It is a super-2 number, since 2×143301536232 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14330153627) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7165076811 + 7165076812.
It is an arithmetic number, because the mean of its divisors is an integer number (7165076812).
Almost surely, 214330153623 is an apocalyptic number.
14330153623 is a deficient number, since it is larger than the sum of its proper divisors (1).
14330153623 is an equidigital number, since it uses as much as digits as its factorization.
14330153623 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 31.
Adding to 14330153623 its reverse (32635103341), we get a palindrome (46965256964).
The spelling of 14330153623 in words is "fourteen billion, three hundred thirty million, one hundred fifty-three thousand, six hundred twenty-three".
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