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14331050413 is a prime number
BaseRepresentation
bin11010101100011001…
…00111100110101101
31100222202101210100221
431112030213212231
5213322222103123
610330020051341
71015064630041
oct152614474655
940882353327
1014331050413
116094560319
12293b533b51
13147508bab4
1499d450021
1558d22725d
hex3563279ad

14331050413 has 2 divisors, whose sum is σ = 14331050414. Its totient is φ = 14331050412.

The previous prime is 14331050401. The next prime is 14331050417. The reversal of 14331050413 is 31405013341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10598084809 + 3732965604 = 102947^2 + 61098^2 .

It is a cyclic number.

It is not a de Polignac number, because 14331050413 - 213 = 14331042221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14331050417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7165525206 + 7165525207.

It is an arithmetic number, because the mean of its divisors is an integer number (7165525207).

Almost surely, 214331050413 is an apocalyptic number.

It is an amenable number.

14331050413 is a deficient number, since it is larger than the sum of its proper divisors (1).

14331050413 is an equidigital number, since it uses as much as digits as its factorization.

14331050413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 14331050413 its reverse (31405013341), we get a palindrome (45736063754).

The spelling of 14331050413 in words is "fourteen billion, three hundred thirty-one million, fifty thousand, four hundred thirteen".