14331113320 has 16 divisors (see below), whose sum is σ = 32245005060. Its totient is φ = 5732445312.

The previous prime is 14331113317. The next prime is 14331113347. The reversal of 14331113320 is 2331113341.

It can be written as a sum of positive squares in 2 ways, for example, as 12939972516 + 1391140804 = 113754^2 + 37298^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14331113291 and 14331113300.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 179138877 + ... + 179138956.

Almost surely, 2^14331113320 is an apocalyptic number.

14331113320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14331113320 is an abundant number, since it is smaller than the sum of its proper divisors (17913891740).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14331113320 is a wasteful number, since it uses less digits than its factorization.

14331113320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 358277844 (or 358277840 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 14331113320 its reverse (2331113341), we get a palindrome (16662226661).

The spelling of 14331113320 in words is "fourteen billion, three hundred thirty-one million, one hundred thirteen thousand, three hundred twenty".