Base | Representation |
---|---|
bin | 1000010101111000110… |
… | …0110000001011011101 |
3 | 111200220211011220000002 |
4 | 2011132030300023131 |
5 | 4322001431302031 |
6 | 145500535144045 |
7 | 13232314432034 |
oct | 2053614601335 |
9 | 450824156002 |
10 | 143314322141 |
11 | 55863220451 |
12 | 23937815025 |
13 | 1068c41a263 |
14 | 6d1789571b |
15 | 3adbba2ccb |
hex | 215e3302dd |
143314322141 has 2 divisors, whose sum is σ = 143314322142. Its totient is φ = 143314322140.
The previous prime is 143314322101. The next prime is 143314322143. The reversal of 143314322141 is 141223413341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 134282670916 + 9031651225 = 366446^2 + 95035^2 .
It is a cyclic number.
It is not a de Polignac number, because 143314322141 - 26 = 143314322077 is a prime.
Together with 143314322143, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143314322143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71657161070 + 71657161071.
It is an arithmetic number, because the mean of its divisors is an integer number (71657161071).
Almost surely, 2143314322141 is an apocalyptic number.
It is an amenable number.
143314322141 is a deficient number, since it is larger than the sum of its proper divisors (1).
143314322141 is an equidigital number, since it uses as much as digits as its factorization.
143314322141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6912, while the sum is 29.
Adding to 143314322141 its reverse (141223413341), we get a palindrome (284537735482).
The spelling of 143314322141 in words is "one hundred forty-three billion, three hundred fourteen million, three hundred twenty-two thousand, one hundred forty-one".
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