Base | Representation |
---|---|
bin | 11010101100111000… |
… | …01011101011000111 |
3 | 1101000001002001221021 |
4 | 31112130023223013 |
5 | 213324243132221 |
6 | 10330243332011 |
7 | 1015144411555 |
oct | 152634135307 |
9 | 41001061837 |
10 | 14335130311 |
11 | 6096897637 |
12 | 2940981007 |
13 | 1475b89b38 |
14 | 99dbd2bd5 |
15 | 58d781041 |
hex | 35670bac7 |
14335130311 has 2 divisors, whose sum is σ = 14335130312. Its totient is φ = 14335130310.
The previous prime is 14335130309. The next prime is 14335130347. The reversal of 14335130311 is 11303153341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14335130311 - 21 = 14335130309 is a prime.
It is a super-2 number, since 2×143351303112 (a number of 21 digits) contains 22 as substring.
Together with 14335130309, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14335133311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7167565155 + 7167565156.
It is an arithmetic number, because the mean of its divisors is an integer number (7167565156).
Almost surely, 214335130311 is an apocalyptic number.
14335130311 is a deficient number, since it is larger than the sum of its proper divisors (1).
14335130311 is an equidigital number, since it uses as much as digits as its factorization.
14335130311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 14335130311 its reverse (11303153341), we get a palindrome (25638283652).
The spelling of 14335130311 in words is "fourteen billion, three hundred thirty-five million, one hundred thirty thousand, three hundred eleven".
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