Base | Representation |
---|---|
bin | 11010101100111010… |
… | …10001000011100101 |
3 | 1101000001121111202211 |
4 | 31112131101003211 |
5 | 213324331231001 |
6 | 10330253403421 |
7 | 1015150004242 |
oct | 152635210345 |
9 | 41001544684 |
10 | 14335414501 |
11 | 6096a71101 |
12 | 2940a99571 |
13 | 1475c592b5 |
14 | 99dc685c9 |
15 | 58d7da351 |
hex | 3567510e5 |
14335414501 has 2 divisors, whose sum is σ = 14335414502. Its totient is φ = 14335414500.
The previous prime is 14335414477. The next prime is 14335414517. The reversal of 14335414501 is 10541453341.
14335414501 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14208401601 + 127012900 = 119199^2 + 11270^2 .
It is a cyclic number.
It is not a de Polignac number, because 14335414501 - 217 = 14335283429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14335414571) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7167707250 + 7167707251.
It is an arithmetic number, because the mean of its divisors is an integer number (7167707251).
Almost surely, 214335414501 is an apocalyptic number.
It is an amenable number.
14335414501 is a deficient number, since it is larger than the sum of its proper divisors (1).
14335414501 is an equidigital number, since it uses as much as digits as its factorization.
14335414501 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 14335414501 its reverse (10541453341), we get a palindrome (24876867842).
The spelling of 14335414501 in words is "fourteen billion, three hundred thirty-five million, four hundred fourteen thousand, five hundred one".
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