14336142110533 has 4 divisors (see below), whose sum is σ = 14350608450688. Its totient is φ = 14321675770380.

The previous prime is 14336142110449. The next prime is 14336142110551. The reversal of 14336142110533 is 33501124163341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14336142110533 is a prime.

It is a super-2 number, since 2×14336142110533² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14336142110492 and 14336142110501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14336142510533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7233168591 + ... + 7233170572.

It is an arithmetic number, because the mean of its divisors is an integer number (3587652112672).

Almost surely, 2^{14336142110533} is an apocalyptic number.

It is an amenable number.

14336142110533 is a deficient number, since it is larger than the sum of its proper divisors (14466340155).

14336142110533 is an equidigital number, since it uses as much as digits as its factorization.

14336142110533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14466340154.

The product of its (nonzero) digits is 77760, while the sum is 37.

Adding to 14336142110533 its reverse (33501124163341), we get a palindrome (47837266273874).

The spelling of 14336142110533 in words is "fourteen trillion, three hundred thirty-six billion, one hundred forty-two million, one hundred ten thousand, five hundred thirty-three".