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143400004357 is a prime number
BaseRepresentation
bin1000010110001101001…
…1100110101100000101
3111201010210101222220111
42011203103212230011
54322140400114412
6145513235433021
713234404632311
oct2054323465405
9451123358814
10143400004357
11558a76227a5
1223960455771
13106a40b9aac
146d24ddab41
153ae447a2a7
hex21634e6b05

143400004357 has 2 divisors, whose sum is σ = 143400004358. Its totient is φ = 143400004356.

The previous prime is 143400004313. The next prime is 143400004361. The reversal of 143400004357 is 753400004341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141823040836 + 1576963521 = 376594^2 + 39711^2 .

It is a cyclic number.

It is not a de Polignac number, because 143400004357 - 27 = 143400004229 is a prime.

It is a super-2 number, since 2×1434000043572 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143400004367) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71700002178 + 71700002179.

It is an arithmetic number, because the mean of its divisors is an integer number (71700002179).

Almost surely, 2143400004357 is an apocalyptic number.

It is an amenable number.

143400004357 is a deficient number, since it is larger than the sum of its proper divisors (1).

143400004357 is an equidigital number, since it uses as much as digits as its factorization.

143400004357 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 31.

Adding to 143400004357 its reverse (753400004341), we get a palindrome (896800008698).

The spelling of 143400004357 in words is "one hundred forty-three billion, four hundred million, four thousand, three hundred fifty-seven".