Base | Representation |
---|---|
bin | 1101000010101101000100… |
… | …1111000000001111010111 |
3 | 1212202220100000011100001020 |
4 | 3100223101033000033113 |
5 | 3334422021432032320 |
6 | 50255431154332223 |
7 | 3010016216035506 |
oct | 320532117001727 |
9 | 55686300140036 |
10 | 14340111205335 |
11 | 4629674a25163 |
12 | 173726228a073 |
13 | 800360b9cc86 |
14 | 3780ca84883d |
15 | 19d044c0d940 |
hex | d0ad13c03d7 |
14340111205335 has 32 divisors (see below), whose sum is σ = 24295770659520. Its totient is φ = 7197600073728.
The previous prime is 14340111205331. The next prime is 14340111205349. The reversal of 14340111205335 is 53350211104341.
It is not a de Polignac number, because 14340111205335 - 22 = 14340111205331 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14340111205296 and 14340111205305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14340111205331) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 976669 + ... + 5443721.
It is an arithmetic number, because the mean of its divisors is an integer number (759242833110).
Almost surely, 214340111205335 is an apocalyptic number.
14340111205335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14340111205335 is a deficient number, since it is larger than the sum of its proper divisors (9955659454185).
14340111205335 is a wasteful number, since it uses less digits than its factorization.
14340111205335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4479667.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 14340111205335 its reverse (53350211104341), we get a palindrome (67690322309676).
The spelling of 14340111205335 in words is "fourteen trillion, three hundred forty billion, one hundred eleven million, two hundred five thousand, three hundred thirty-five".
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