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143401413433 is a prime number
BaseRepresentation
bin1000010110001101100…
…0111110101100111001
3111201010220001120210111
42011203120332230321
54322141230212213
6145513325544321
713234422621355
oct2054330765471
9451126046714
10143401413433
11558a83a5423
1223960a150a1
13106a4491275
146d25286465
153ae4657a3d
hex216363eb39

143401413433 has 2 divisors, whose sum is σ = 143401413434. Its totient is φ = 143401413432.

The previous prime is 143401413431. The next prime is 143401413473. The reversal of 143401413433 is 334314104341.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120622152249 + 22779261184 = 347307^2 + 150928^2 .

It is a cyclic number.

It is not a de Polignac number, because 143401413433 - 21 = 143401413431 is a prime.

Together with 143401413431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 143401413395 and 143401413404.

It is not a weakly prime, because it can be changed into another prime (143401413431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71700706716 + 71700706717.

It is an arithmetic number, because the mean of its divisors is an integer number (71700706717).

Almost surely, 2143401413433 is an apocalyptic number.

It is an amenable number.

143401413433 is a deficient number, since it is larger than the sum of its proper divisors (1).

143401413433 is an equidigital number, since it uses as much as digits as its factorization.

143401413433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 143401413433 its reverse (334314104341), we get a palindrome (477715517774).

The spelling of 143401413433 in words is "one hundred forty-three billion, four hundred one million, four hundred thirteen thousand, four hundred thirty-three".