143411161053 has 8 divisors (see below), whose sum is σ = 195283283328. Its totient is φ = 93573239744.

The previous prime is 143411161051. The next prime is 143411161111. The reversal of 143411161053 is 350161114341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 143411161053 - 2¹ = 143411161051 is a prime.

It is a super-2 number, since 2×143411161053² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 143411161053.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143411161051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 508550076 + ... + 508550357.

It is an arithmetic number, because the mean of its divisors is an integer number (24410410416).

Almost surely, 2^143411161053 is an apocalyptic number.

It is an amenable number.

143411161053 is a deficient number, since it is larger than the sum of its proper divisors (51872122275).

143411161053 is a wasteful number, since it uses less digits than its factorization.

143411161053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1017100483.

The product of its (nonzero) digits is 4320, while the sum is 30.

Adding to 143411161053 its reverse (350161114341), we get a palindrome (493572275394).

The spelling of 143411161053 in words is "one hundred forty-three billion, four hundred eleven million, one hundred sixty-one thousand, fifty-three".