Base | Representation |
---|---|
bin | 1101000010110000111101… |
… | …0110011110100101100010 |
3 | 1212210000000122010212120010 |
4 | 3100230033112132211202 |
5 | 3334431140224231114 |
6 | 50300122423225350 |
7 | 3010054102115205 |
oct | 320541726364542 |
9 | 55700018125503 |
10 | 14341153352034 |
11 | 462a05a215423 |
12 | 17374b32a8256 |
13 | 800498a75b22 |
14 | 37818900793c |
15 | 19d0a6467c59 |
hex | d0b0f59e962 |
14341153352034 has 64 divisors (see below), whose sum is σ = 30447212100480. Its totient is φ = 4487675166720.
The previous prime is 14341153352027. The next prime is 14341153352083. The reversal of 14341153352034 is 43025335114341.
14341153352034 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 14341153351983 and 14341153352001.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 559467282 + ... + 559492914.
It is an arithmetic number, because the mean of its divisors is an integer number (475737689070).
Almost surely, 214341153352034 is an apocalyptic number.
14341153352034 is an abundant number, since it is smaller than the sum of its proper divisors (16106058748446).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14341153352034 is a wasteful number, since it uses less digits than its factorization.
14341153352034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39475.
The product of its (nonzero) digits is 259200, while the sum is 39.
Adding to 14341153352034 its reverse (43025335114341), we get a palindrome (57366488466375).
The spelling of 14341153352034 in words is "fourteen trillion, three hundred forty-one billion, one hundred fifty-three million, three hundred fifty-two thousand, thirty-four".
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